beremiz

Fix invalid python3 syntax

2019-03-13, Andrey Skvortsov
2747d6e72eb8
Fix invalid python3 syntax

Syntax checking using python3 ...
Python 3.7.2+
File "./connectors/PYRO/__init__.py", line 76
except Exception, e:
^
SyntaxError: invalid syntax

Syntax error in ./connectors/PYRO/__init__.py
File "./connectors/PYRO/PSK_Adapter.py", line 40
except ProtocolError, x:
^
SyntaxError: invalid syntax

Syntax error in ./s.py
File "./runtime/Worker.py", line 67
raise _job.exc_info[0], _job.exc_info[1], _job.exc_info[2]
^
SyntaxError: invalid syntax
# the platform name (PyV8, smjs, Mozilla, IE6, Opera, Safari etc.)
platform = '' # to be updated by app, on compile
# a dictionary of module override names (platform-specific)
overrides = {} # to be updated by app, on compile
# the remote path for loading modules
loadpath = None
stacktrace = None
appname = None
def setloadpath(lp):
global loadpath
loadpath = lp
def setappname(an):
global appname
appname = an
def getloadpath():
return loadpath
def addoverride(module_name, path):
overrides[module_name] = path
def addstack(linedebug):
JS("""
if (pyjslib.bool((sys.stacktrace === null))) {
sys.stacktrace = new pyjslib.List([]);
}
sys.stacktrace.append(linedebug);
""")
def popstack():
JS("""
sys.stacktrace.pop()
""")
def printstack():
JS("""
var res = '';
var __l = sys.stacktrace.__iter__();
try {
while (true) {
var l = __l.next();
res += ( l + '\\n' ) ;
}
} catch (e) {
if (e != pyjslib.StopIteration) {
throw e;
}
}
return res;
""")